2025年三种获取当天剩余时间的简洁方式

科技前沿 • 2025-04-09 13:23 • 阅读 36

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三种获取当天剩余时间的简洁方式，分别使用DateUtils、DateTime和 LocalDateTime

import org.apache.commons.lang.time.DateUtils; import org.joda.time.DateTime; import org.joda.time.Duration; import org.junit.Test; import java.time.LocalDateTime; import java.time.temporal.ChronoUnit; import java.util.Calendar; / * Created by Administrator on 2016/12/12. */ public class TimeTest { @Test public void getTime() { //方法一 long milliSecondsLeftToday =  - DateUtils.getFragmentInMilliseconds(Calendar.getInstance(), Calendar.DATE); long secondsLeftToday = 86400 - DateUtils.getFragmentInSeconds(Calendar.getInstance(), Calendar.DATE); System.out.println("当天剩余毫秒1：" + milliSecondsLeftToday); System.out.println("当天剩余秒1：" + secondsLeftToday); //方法二 DateTime dateTime = new DateTime().millisOfDay().withMaximumValue(); long millSeconds2 = new Duration(new DateTime(), dateTime).getMillis(); long count = new Duration(new DateTime(), dateTime).getStandardSeconds(); System.out.println("当天剩余毫秒2：" + millSeconds2); System.out.println("当天剩余秒2：" + count); //方法三:LocalDateTime和ChronoUnit为1.8新增 LocalDateTime midnight = LocalDateTime.now().plusDays(1).withHour(0).withMinute(0).withSecond(0).withNano(0); long millSeconds = ChronoUnit.MILLIS.between(LocalDateTime.now(),midnight); long seconds = ChronoUnit.SECONDS.between(LocalDateTime.now(), midnight); System.out.println("当天剩余毫秒3：" + millSeconds); System.out.println("当天剩余秒3：" + seconds); } }

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2025年三种获取当天剩余时间的简洁方式

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