2025年经典数字金字塔合集——python解法

科技前沿 • 2025-03-11 17:36 • 阅读 43

大家好，我是讯享网，很高兴认识大家。

1.题目：

代码：

L = int(input("请输入行数：")) for a in range(1,L+1): if a==1: for b in range(L-a,0,-1) : print(" ",end="") print(1) else: for b in range(L-a,0,-1) : print(" ",end="") for b in range(a,0,-1): if b==1: print(b,end="") else: print(b,end=" ") for b in range(2,a+1): if b==a: print(" %s"%b) else: print(" %s"%b,end="")

讯享网

运行截图：

2.题目：

代码：

讯享网#1 for a in range(1,7): for b in range(1,a+1): print(b,end = " ") print() print() #2 for a in range(6,0,-1): for b in range(1,a+1): print(b,end = " ") print() print() #3 line = 6 for a in range(1,line+1): kong = line-a for b in range(0,kong): print(" ",end = " ") 2 for b in range(a,0,-1): print(b,end = " ") print() print() #4 line = 6 for a in range(1,7): for b in range(a): print(" ",end=" ") for b in range(1,line-b+1): print(b,end=" ") print()

运行截图：

3.题目：

代码：

L = int(input("请输入行数：")) for a in range(1,L+1): if a==1: for b in range(L-a,0,-1) : print(" ",end="") print(1) else: for b in range(L-a,0,-1) : print(" ",end="") for b in range(1,a+1): if b==a: b=1*(2(b-1)) print(b,end="") else: b=1*(2(b-1)) print(b,end=" ") for b in range(a-2,-1,-1): if b==0: b=1*(2b) print(" %s"%b) else: b=1*(2b) print(" %s"%b,end="")

运行截图：

2025年经典数字金字塔合集——python解法

1.题目：

2.题目：

3.题目：

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