java基础第十章答案

java基础第十章答案Java 语言程序设计 基础篇 第 10 版梁勇著 第十章练习题答案 10 1 PUbliC ClaSS EXerCiSe10 01 PUbliC StatiC VOid main String args Time timel new Time SyStem out Pri n tln 11011 厂 timel getHou O

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}

}

}

}

《Java语言程序设计(基础篇)》(第10版梁勇著)

第十章练习题答案

10.1

PUbliC ClaSS EXerCiSe10_01 {

PUbliC StatiC VOid main(String[] args) {

Time timel = new Time();

SyStem .out. Pri n*tln (11011厂:,,+ timel .getHou^O + ,, Min ute: ,, ÷

timel .getM in ute( ) + ,, SeCOnd : ,, + timel .getSeco nd());

Time time2 = new Time();

SyStem .out. Pri n*tln (11011厂:,,+ time2 .getHou^O + ,, Min ute: ,, ÷

time2. getMinute ( ) + ,, SeCOnd : ,, + time2. getSecond ()); }

}

ClaSS Time {

PriVate int hour;

PriVate int minute;

PriVate int SeCOnd;

PUbliC Time() {

this(System.CUrrentTimeMillis());

}

PUbliC Time(Iong elapsedTime) {

SetTime(elapsedTime);

}

PUbliC Time(int hour^ int minUte? int SeCOnd) {

this.hour = hour;

this.minute = minute;

this.second = SeCOnd;

}

PUbliC int getHour() {

return hour;

}

PUbliC int getMinute() {

return minute;

PUbliC int getSecond() {

return SeCOnd;

}

PUbliC VOid SetTime(IOng elapsedTime) {

// Obtain the total SeCOnds SinCe the midnight^ Jan IJ 1970 IOng totalSecOndS = elapsedTime / 1000;

// COmPUte the CUrrent SeCOnd in the minUte in the HOUr SeCOnd = (int)(totalSeconds % 60);

// Obtain the total minUteS

IOng totalMinutes = totalSeconds / 60;

// COmPUte the CUrrent minutR in the hour

minute = (int)(totalMinutes % 60);

// Obtain the total hours

int totalHours = (int)(totalMinutes / 60);

// COmPUte the CUrrent hour

hour = (int)(totalHours % 24);

}

}

10.2

PUbliC ClaSS EXerCiSe10_02 {

PUbliC StatiC VOid main(String[] args) {

BMl bmil = new BMI(,,3ohn Doe,,. 18, 145java基础第十章答案, 5, 10);

SyStem.out. PrintIn( The BMl for ,, + bmil.getName( ) + l, is ,, + bmil.getBMI() + l, ,, + bmil.getStatus());

BMl bmi2 = new BMI(,,Peter KingJ 215, 5, 10);

SyStem.out. PrintIn( The BMl for ,, + bmi2.getName( ) + l, is ,, + bmi2.getBMI( ) + l, ,, + bmi2.getStatus());

}

static ClaSS BMl {

PriVate String name;

PriVate int age;

PriVate double weight; // in POUnds

PriVate double height; // in inCheS

PUbliC final double KILOGRAMS_PER_POUND = 0

PUbliC final double METERS-PER_INCH = 0.0254;

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