//这里使用无向图 #include <iostream>using namespace std;const int MAXN = 2001; const int INF = ;int n,e; int w[MAXN][MAXN]; int mincount[MAXN]; //从初始顶点到该顶点的最小权值
讯享网void init() {讯享网</span><span style="color: rgba(0, 0, 255, 1)">int</span><span style="color: rgba(0, 0, 0, 1)"> i,j; </span><span style="color: rgba(0, 0, 255, 1)">int</span><span style="color: rgba(0, 0, 0, 1)"> tx,ty; </span><span style="color: rgba(0, 0, 255, 1)">for</span>(i = <span style="color: rgba(128, 0, 128, 1)">0</span>; i<=MAXN; i++<span style="color: rgba(0, 0, 0, 1)">) </span><span style="color: rgba(0, 0, 255, 1)">for</span>(j =<span style="color: rgba(128, 0, 128, 1)">0</span>; j<MAXN; j++<span style="color: rgba(0, 0, 0, 1)">) w[i][j] </span>=<span style="color: rgba(0, 0, 0, 1)"> INF; cin </span>>> n >><span style="color: rgba(0, 0, 0, 1)"> e; </span><span style="color: rgba(0, 0, 255, 1)">for</span>(i = <span style="color: rgba(128, 0, 128, 1)">1</span>; i<=e; i++<span style="color: rgba(0, 0, 0, 1)">) { cin </span>>> tx >> ty >><span style="color: rgba(0, 0, 0, 1)"> w[tx][ty]; w[tx][ty] </span>=<span style="color: rgba(0, 0, 0, 1)"> w[ty][tx]; }}void prim(int s) //从标号为s处开始生成树 {</span><span style="color: rgba(0, 0, 255, 1)">int</span> i,j,cnt = <span style="color: rgba(128, 0, 128, 1)">0</span>,min; <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)"> cnt 是生成树所有边的权值之和</span> <span style="color: rgba(0, 0, 255, 1)">int</span><span style="color: rgba(0, 0, 0, 1)"> k; </span><span style="color: rgba(0, 0, 255, 1)">for</span>(i = <span style="color: rgba(128, 0, 128, 1)">1</span>; i<= n; i++<span style="color: rgba(0, 0, 0, 1)">) mincount[i] </span>= w[s][i]; <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)"> 初始化,设w[1][i]是初始点k到i的最小权值,如果没有就设为INF</span> mincount[s] = <span style="color: rgba(128, 0, 128, 1)">0</span><span style="color: rgba(0, 0, 0, 1)">; </span><span style="color: rgba(0, 0, 255, 1)">for</span>(i = <span style="color: rgba(128, 0, 128, 1)">1</span>; i < n; i++) <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">一共有n-1次</span>{讯享网min </span>=<span style="color: rgba(0, 0, 0, 1)"> INF; </span><span style="color: rgba(0, 0, 255, 1)">for</span>(j = <span style="color: rgba(128, 0, 128, 1)">1</span>; j <= n; j++<span style="color: rgba(0, 0, 0, 1)">) { </span><span style="color: rgba(0, 0, 255, 1)">if</span>(mincount[j]!=<span style="color: rgba(128, 0, 128, 1)">0</span> && mincount[j]<<span style="color: rgba(0, 0, 0, 1)">min) { min </span>=<span style="color: rgba(0, 0, 0, 1)"> mincount[j]; k </span>= j; <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">记录该点</span>}mincount[k] </span>= <span style="color: rgba(128, 0, 128, 1)">0</span>;<span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">将该点加入到最小生成树中</span> cnt += min; <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">将这条边权值加入到最小生成树中</span> <span style="color: rgba(0, 0, 255, 1)">for</span>(j = <span style="color: rgba(128, 0, 128, 1)">1</span>;j<=n;j++) <span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">修正初始点到每个点的最小权值</span>{讯享网</span><span style="color: rgba(0, 0, 255, 1)">if</span>(w[k][j]<<span style="color: rgba(0, 0, 0, 1)">mincount[j]) mincount[j] </span>=<span style="color: rgba(0, 0, 0, 1)"> w[k][j]; } } } cout </span><< cnt <<<span style="color: rgba(0, 0, 0, 1)"> endl;}int main() {init(); prim(</span><span style="color: rgba(128, 0, 128, 1)">1</span><span style="color: rgba(0, 0, 0, 1)">); </span><span style="color: rgba(0, 0, 255, 1)">return</span> <span style="color: rgba(128, 0, 128, 1)">0</span><span style="color: rgba(0, 0, 0, 1)">;}
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